Change the initial catalog of Git Bash
Git bash not always opens in the correct directory. In my case it has opened in /h/ for whatever reason. Since I wanted it to open i the ./repos, i decided to modify bash.bashrc
  1. Navigate to the directory of your Gir installation and /etc
  1. Edit bash.bashrc
  1. At the very end of the file add the following command:

Comments

Post a Comment

Popular posts from this blog

VBA Randomize a 3x3 Filter for Convoluted Neural Network

Image
EXCEL FOR FINANCE How to Randomize a 3x3 Filter for a Convoluted Neural Network in VBA Option Explicit Private Sub CommandButton1_Click()    Application.ScreenUpdating = False    Application.DisplayStatusBar = False     Dim i, j As Integer     Dim randomNumber As Double        For i = 1 To 3       Randomize                     For j = 1 To 3               randomNumber = rnd()                 'Application.ActiveWorkbook.ActiveSheet.Cells(i + 20, j + 29).Select                Application.ActiveWorkbook.Active...
Read more

Adding IQ Driver to LINQPad and connecting to ORACLE Database

Image
Adding IQ Driver to LINQPad and connecting to ORACLE Database Download the IQ Driver from: http://www.linqpad.net/richclient/datacontextdrivers.aspx Open LINQPad Add connection View more drivers > Browse You will now be able to see the new driver on the list. Connect to Oracle Open LINQPad Click on Add connection Select the IQ Driver Select Oracle Provide Server IP or DNS name User name and Password On the Advanced tab provide SID and the port number Test the connection
Read more

Upload a file to a Web server in ASP.NET by using Visual C# .NET

Image
Upload a file to a Web server in ASP.NET by using Visual C# .NET Open the Visual Studio Click New > Project ASP.NET WebApplication Name it accordingly When the Project gets created, right click on it and click on Add > New Item > Web Form Name the form FileUpload.aspx Open the FileUpload.aspx the following code <% @ Page Language ="C#" AutoEventWireup ="true" CodeBehind ="FileUpload.aspx.cs" Inherits ="ASPFileUpload.FileUpload" %> <! DOCTYPE html > < html xmlns ="http://www.w3.org/1999/xhtml"> < head runat ="server">     < title > FileUpload </ title > </ head > < body >     < form id ="form1" enctype ="multipart/form-data" runat ="server">         < p >< input type ="file" id ="File1" name ="File1" runat ="server...
Read more